Question
Answer
$$3(y+2)^2=3y^2+12y+12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3(y+2)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3(1y^2+4y+4) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3y^2+12y+12\end{aligned} $$ | |
| ① | Find $ \left(y+2\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ y } $ and $ B = \color{red}{ 2 }$. $$ \begin{aligned}\left(y+2\right)^2 = \color{blue}{y^2} +2 \cdot y \cdot 2 + \color{red}{2^2} = y^2+4y+4\end{aligned} $$ |
| ② | Multiply $ \color{blue}{3} $ by $ \left( y^2+4y+4\right) $ $$ \color{blue}{3} \cdot \left( y^2+4y+4\right) = 3y^2+12y+12 $$ |
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