Tap the blue circles to see an explanation.
| $$ \begin{aligned}3(x+1)-2(x+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3x+3-(2x+2) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3x+3-2x-2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}x+1\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3} $ by $ \left( x+1\right) $ $$ \color{blue}{3} \cdot \left( x+1\right) = 3x+3 $$Multiply $ \color{blue}{2} $ by $ \left( x+1\right) $ $$ \color{blue}{2} \cdot \left( x+1\right) = 2x+2 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( 2x+2 \right) = -2x-2 $$ |
| ③ | Combine like terms: $$ \color{blue}{3x} + \color{red}{3} \color{blue}{-2x} \color{red}{-2} = \color{blue}{x} + \color{red}{1} $$ |