Question
Answer
$$3(x-2)(x+1)=3x^2-3x-6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3(x-2)(x+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(3x-6)(x+1) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3x^2+3x-6x-6 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}3x^2-3x-6\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3} $ by $ \left( x-2\right) $ $$ \color{blue}{3} \cdot \left( x-2\right) = 3x-6 $$ |
| ② | Multiply each term of $ \left( \color{blue}{3x-6}\right) $ by each term in $ \left( x+1\right) $. $$ \left( \color{blue}{3x-6}\right) \cdot \left( x+1\right) = 3x^2+3x-6x-6 $$ |
| ③ | Combine like terms: $$ 3x^2+ \color{blue}{3x} \color{blue}{-6x} -6 = 3x^2 \color{blue}{-3x} -6 $$ |
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