Tap the blue circles to see an explanation.
| $$ \begin{aligned}3(x^2-1)+2(2x^2+2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3x^2-3+4x^2+4 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}7x^2+1\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3} $ by $ \left( x^2-1\right) $ $$ \color{blue}{3} \cdot \left( x^2-1\right) = 3x^2-3 $$Multiply $ \color{blue}{2} $ by $ \left( 2x^2+2\right) $ $$ \color{blue}{2} \cdot \left( 2x^2+2\right) = 4x^2+4 $$ |
| ② | Combine like terms: $$ \color{blue}{3x^2} \color{red}{-3} + \color{blue}{4x^2} + \color{red}{4} = \color{blue}{7x^2} + \color{red}{1} $$ |