Question
Answer
$$3(n^3+7n^2-4)=3n^3+21n^2-12$$
Explanation
| $$ \begin{aligned}3(n^3+7n^2-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3n^3+21n^2-12\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3} $ by $ \left( n^3+7n^2-4\right) $ $$ \color{blue}{3} \cdot \left( n^3+7n^2-4\right) = 3n^3+21n^2-12 $$ |
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