Question
Answer
$$3(7a^{10}-4a^9-5a^{10})=6a^{10}-12a^9$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3(7a^{10}-4a^9-5a^{10})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3(2a^{10}-4a^9) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6a^{10}-12a^9\end{aligned} $$ | |
| ① | Combine like terms: $$ \color{blue}{7a^{10}} -4a^9 \color{blue}{-5a^{10}} = \color{blue}{2a^{10}} -4a^9 $$ |
| ② | Multiply $ \color{blue}{3} $ by $ \left( 2a^{10}-4a^9\right) $ $$ \color{blue}{3} \cdot \left( 2a^{10}-4a^9\right) = 6a^{10}-12a^9 $$ |
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