Question
Answer
$$3(2y-5)+7(y+2)=13y-1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3(2y-5)+7(y+2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6y-15+7y+14 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}13y-1\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3} $ by $ \left( 2y-5\right) $ $$ \color{blue}{3} \cdot \left( 2y-5\right) = 6y-15 $$Multiply $ \color{blue}{7} $ by $ \left( y+2\right) $ $$ \color{blue}{7} \cdot \left( y+2\right) = 7y+14 $$ |
| ② | Combine like terms: $$ \color{blue}{6y} \color{red}{-15} + \color{blue}{7y} + \color{red}{14} = \color{blue}{13y} \color{red}{-1} $$ |
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