Question
Answer
$$2xy(3xy+2x-1)-3x^2y=6x^2y^2+x^2y-2xy$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2xy(3xy+2x-1)-3x^2y& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^2y^2+4x^2y-2xy-3x^2y \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6x^2y^2+x^2y-2xy\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2xy} $ by $ \left( 3xy+2x-1\right) $ $$ \color{blue}{2xy} \cdot \left( 3xy+2x-1\right) = 6x^2y^2+4x^2y-2xy $$ |
| ② | Combine like terms: $$ 6x^2y^2+ \color{blue}{4x^2y} -2xy \color{blue}{-3x^2y} = 6x^2y^2+ \color{blue}{x^2y} -2xy $$ |
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