Tap the blue circles to see an explanation.
| $$ \begin{aligned}2x(x-8)(5x+9)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(2x^2-16x)(5x+9) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}10x^3+18x^2-80x^2-144x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}10x^3-62x^2-144x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2x} $ by $ \left( x-8\right) $ $$ \color{blue}{2x} \cdot \left( x-8\right) = 2x^2-16x $$ |
| ② | Multiply each term of $ \left( \color{blue}{2x^2-16x}\right) $ by each term in $ \left( 5x+9\right) $. $$ \left( \color{blue}{2x^2-16x}\right) \cdot \left( 5x+9\right) = 10x^3+18x^2-80x^2-144x $$ |
| ③ | Combine like terms: $$ 10x^3+ \color{blue}{18x^2} \color{blue}{-80x^2} -144x = 10x^3 \color{blue}{-62x^2} -144x $$ |