| $$ \begin{aligned}2x(6x^2+3x-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}12x^3+6x^2-2x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2x} $ by $ \left( 6x^2+3x-1\right) $ $$ \color{blue}{2x} \cdot \left( 6x^2+3x-1\right) = 12x^3+6x^2-2x $$ |