| $$ \begin{aligned}2x(3x^2+5x-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^3+10x^2-4x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2x} $ by $ \left( 3x^2+5x-2\right) $ $$ \color{blue}{2x} \cdot \left( 3x^2+5x-2\right) = 6x^3+10x^2-4x $$ |