| $$ \begin{aligned}2r(-3r^2-r)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-6r^3-2r^2\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2r} $ by $ \left( -3r^2-r\right) $ $$ \color{blue}{2r} \cdot \left( -3r^2-r\right) = -6r^3-2r^2 $$ |