Question
Answer
$$2(x+8)^2+10=2x^2+32x+138$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2(x+8)^2+10& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2(x^2+16x+64)+10 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^2+32x+128+10 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}2x^2+32x+138\end{aligned} $$ | |
| ① | Find $ \left(x+8\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ x } $ and $ B = \color{red}{ 8 }$. $$ \begin{aligned}\left(x+8\right)^2 = \color{blue}{x^2} +2 \cdot x \cdot 8 + \color{red}{8^2} = x^2+16x+64\end{aligned} $$ |
| ② | Multiply $ \color{blue}{2} $ by $ \left( x^2+16x+64\right) $ $$ \color{blue}{2} \cdot \left( x^2+16x+64\right) = 2x^2+32x+128 $$ |
| ③ | Combine like terms: $$ 2x^2+32x+ \color{blue}{128} + \color{blue}{10} = 2x^2+32x+ \color{blue}{138} $$ |
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