Question
Answer
$$2(x-4)(x+3)=2x^2-2x-24$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2(x-4)(x+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(2x-8)(x+3) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^2+6x-8x-24 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}2x^2-2x-24\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2} $ by $ \left( x-4\right) $ $$ \color{blue}{2} \cdot \left( x-4\right) = 2x-8 $$ |
| ② | Multiply each term of $ \left( \color{blue}{2x-8}\right) $ by each term in $ \left( x+3\right) $. $$ \left( \color{blue}{2x-8}\right) \cdot \left( x+3\right) = 2x^2+6x-8x-24 $$ |
| ③ | Combine like terms: $$ 2x^2+ \color{blue}{6x} \color{blue}{-8x} -24 = 2x^2 \color{blue}{-2x} -24 $$ |
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