Question
Answer
$$2(x^4-4x^3-5x^2+22x-12)=2x^4-8x^3-10x^2+44x-24$$
Explanation
| $$ \begin{aligned}2(x^4-4x^3-5x^2+22x-12)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^4-8x^3-10x^2+44x-24\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2} $ by $ \left( x^4-4x^3-5x^2+22x-12\right) $ $$ \color{blue}{2} \cdot \left( x^4-4x^3-5x^2+22x-12\right) = 2x^4-8x^3-10x^2+44x-24 $$ |
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