Tap the blue circles to see an explanation.
| $$ \begin{aligned}2{f^4}^2\frac{f^2}{8f^{12}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2\cdot1f^8\frac{f^2}{8f^{12}} \xlongequal{ } \\[1 em] & \xlongequal{ }2f^8\frac{f^2}{8f^{12}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{2f^{10}}{8f^{12}}\end{aligned} $$ | |
| ① | $$ \left( f^4 \right)^2 = 1^2 \left( f^4 \right)^2 = f^8 $$ |
| ② | Multiply $2f^8$ by $ \dfrac{f^2}{8f^{12}} $ to get $ \dfrac{ 2f^{10} }{ 8f^{12} } $. Step 1: Write $ 2f^8 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 2f^8 \cdot \frac{f^2}{8f^{12}} & \xlongequal{\text{Step 1}} \frac{2f^8}{\color{red}{1}} \cdot \frac{f^2}{8f^{12}} \xlongequal{\text{Step 2}} \frac{ 2f^8 \cdot f^2 }{ 1 \cdot 8f^{12} } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 2f^{10} }{ 8f^{12} } \end{aligned} $$ |