Question
Answer
$$2(6k+3)^2=72k^2+72k+18$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2(6k+3)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2(36k^2+36k+9) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}72k^2+72k+18\end{aligned} $$ | |
| ① | Find $ \left(6k+3\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 6k } $ and $ B = \color{red}{ 3 }$. $$ \begin{aligned}\left(6k+3\right)^2 = \color{blue}{\left( 6k \right)^2} +2 \cdot 6k \cdot 3 + \color{red}{3^2} = 36k^2+36k+9\end{aligned} $$ |
| ② | Multiply $ \color{blue}{2} $ by $ \left( 36k^2+36k+9\right) $ $$ \color{blue}{2} \cdot \left( 36k^2+36k+9\right) = 72k^2+72k+18 $$ |
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