Question
Answer
$$16y\cdot5+4y\cdot5-12y\cdot3+15y\cdot3=109y$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}16y\cdot5+4y\cdot5-12y\cdot3+15y\cdot3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}80y+20y-36y+45y \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} } }}}109y\end{aligned} $$ | |
| ① | $$ 16 y \cdot 5 = 80 y $$ |
| ② | $$ 4 y \cdot 5 = 20 y $$ |
| ③ | $$ 12 y \cdot 3 = 36 y $$ |
| ④ | $$ 15 y \cdot 3 = 45 y $$ |
| ⑤ | Combine like terms: $$ \color{blue}{80y} + \color{red}{20y} \color{green}{-36y} + \color{green}{45y} = \color{green}{109y} $$ |
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