Question
Answer
$$10+2y^3-(8y^3-y^2+5)=-6y^3+y^2+5$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}10+2y^3-(8y^3-y^2+5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}10+2y^3-8y^3+y^2-5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-6y^3+y^2+5\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 8y^3-y^2+5 \right) = -8y^3+y^2-5 $$ |
| ② | Combine like terms: $$ \color{blue}{10} + \color{red}{2y^3} \color{red}{-8y^3} +y^2 \color{blue}{-5} = \color{red}{-6y^3} +y^2+ \color{blue}{5} $$ |
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