Question
Answer
$$10+2y^2-(8y^3-y^2+5y^3)=-13y^3+3y^2+10$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}10+2y^2-(8y^3-y^2+5y^3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}10+2y^2-(13y^3-y^2) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}10+2y^2-13y^3+y^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-13y^3+3y^2+10\end{aligned} $$ | |
| ① | Combine like terms: $$ \color{blue}{8y^3} -y^2+ \color{blue}{5y^3} = \color{blue}{13y^3} -y^2 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( 13y^3-y^2 \right) = -13y^3+y^2 $$ |
| ③ | Combine like terms: $$ 10+ \color{blue}{2y^2} -13y^3+ \color{blue}{y^2} = -13y^3+ \color{blue}{3y^2} +10 $$ |
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