Question
Answer
$$10+2y^2-(4y-4y^2+2)=6y^2-4y+8$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}10+2y^2-(4y-4y^2+2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}10+2y^2-4y+4y^2-2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6y^2-4y+8\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 4y-4y^2+2 \right) = -4y+4y^2-2 $$ |
| ② | Combine like terms: $$ \color{blue}{10} + \color{red}{2y^2} -4y+ \color{red}{4y^2} \color{blue}{-2} = \color{red}{6y^2} -4y+ \color{blue}{8} $$ |
This page was created using
Simplify polynomials calculator