Question
Answer
$$-xy(6y-1)=-6xy^2+xy$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-xy(6y-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(6xy^2-xy) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-6xy^2+xy\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{xy} $ by $ \left( 6y-1\right) $ $$ \color{blue}{xy} \cdot \left( 6y-1\right) = 6xy^2-xy $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(6xy^2-xy \right) = -6xy^2+xy $$ |
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