Question
Answer
$$-w(w^2-3w+8)=-w^3+3w^2-8w$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-w(w^2-3w+8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(1w^3-3w^2+8w) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-w^3+3w^2-8w\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{w} $ by $ \left( w^2-3w+8\right) $ $$ \color{blue}{w} \cdot \left( w^2-3w+8\right) = w^3-3w^2+8w $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(w^3-3w^2+8w \right) = -w^3+3w^2-8w $$ |
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