Question
Answer
$$-7y^2+3y-6-(3y^2+4y+4)=-10y^2-y-10$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-7y^2+3y-6-(3y^2+4y+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-7y^2+3y-6-3y^2-4y-4 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-10y^2-y-10\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 3y^2+4y+4 \right) = -3y^2-4y-4 $$ |
| ② | Combine like terms: $$ \color{blue}{-7y^2} + \color{red}{3y} \color{green}{-6} \color{blue}{-3y^2} \color{red}{-4y} \color{green}{-4} = \color{blue}{-10y^2} \color{red}{-y} \color{green}{-10} $$ |
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