Question
Answer
$$-4y(5y-11)-2y(3y+10)=-26y^2+24y$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-4y(5y-11)-2y(3y+10)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(20y^2-44y)-(6y^2+20y) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-20y^2+44y-(6y^2+20y) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-20y^2+44y-6y^2-20y \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}-26y^2+24y\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{4y} $ by $ \left( 5y-11\right) $ $$ \color{blue}{4y} \cdot \left( 5y-11\right) = 20y^2-44y $$Multiply $ \color{blue}{2y} $ by $ \left( 3y+10\right) $ $$ \color{blue}{2y} \cdot \left( 3y+10\right) = 6y^2+20y $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(20y^2-44y \right) = -20y^2+44y $$ |
| ③ | Remove the parentheses by changing the sign of each term within them. $$ - \left( 6y^2+20y \right) = -6y^2-20y $$ |
| ④ | Combine like terms: $$ \color{blue}{-20y^2} + \color{red}{44y} \color{blue}{-6y^2} \color{red}{-20y} = \color{blue}{-26y^2} + \color{red}{24y} $$ |
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