Question
Answer
$$-3xy(x^2y^3+2xy)=-3x^3y^4-6x^2y^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-3xy(x^2y^3+2xy)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(3x^3y^4+6x^2y^2) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-3x^3y^4-6x^2y^2\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3xy} $ by $ \left( x^2y^3+2xy\right) $ $$ \color{blue}{3xy} \cdot \left( x^2y^3+2xy\right) = 3x^3y^4+6x^2y^2 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(3x^3y^4+6x^2y^2 \right) = -3x^3y^4-6x^2y^2 $$ |
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