Question
Answer
$$-3x(4x-y)=-12x^2+3xy$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-3x(4x-y)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(12x^2-3xy) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-12x^2+3xy\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3x} $ by $ \left( 4x-y\right) $ $$ \color{blue}{3x} \cdot \left( 4x-y\right) = 12x^2-3xy $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(12x^2-3xy \right) = -12x^2+3xy $$ |
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