Question
Answer
$$-3(x-3)^2=-3x^2+18x-27$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-3(x-3)^2& \xlongequal{ }-3(x^2-6x+9) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(3x^2-18x+27) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-3x^2+18x-27\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3} $ by $ \left( x^2-6x+9\right) $ $$ \color{blue}{3} \cdot \left( x^2-6x+9\right) = 3x^2-18x+27 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(3x^2-18x+27 \right) = -3x^2+18x-27 $$ |
This page was created using
Simplify polynomials calculator