Question
Answer
$$-3(x-2)\cdot(2-9x)=27x^2-60x+12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-3(x-2)\cdot(2-9x)& \xlongequal{ }-(3x-6)\cdot(2-9x) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(6x-27x^2-12+54x) \xlongequal{ } \\[1 em] & \xlongequal{ }-(-27x^2+60x-12) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}27x^2-60x+12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3x-6}\right) $ by each term in $ \left( 2-9x\right) $. $$ \left( \color{blue}{3x-6}\right) \cdot \left( 2-9x\right) = 6x-27x^2-12+54x $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(-27x^2+60x-12 \right) = 27x^2-60x+12 $$ |
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