Question
Answer
$$-2x(x^2+4x-3)=-2x^3-8x^2+6x$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-2x(x^2+4x-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(2x^3+8x^2-6x) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-2x^3-8x^2+6x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2x} $ by $ \left( x^2+4x-3\right) $ $$ \color{blue}{2x} \cdot \left( x^2+4x-3\right) = 2x^3+8x^2-6x $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(2x^3+8x^2-6x \right) = -2x^3-8x^2+6x $$ |
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