Tap the blue circles to see an explanation.
| $$ \begin{aligned}-2x(3x-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(6x^2-2x) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-6x^2+2x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2x} $ by $ \left( 3x-1\right) $ $$ \color{blue}{2x} \cdot \left( 3x-1\right) = 6x^2-2x $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(6x^2-2x \right) = -6x^2+2x $$ |