Question
Answer
$$-3g^2(-2g^2-g+3)=6g^4+3g^3-9g^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-3g^2(-2g^2-g+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(-6g^4-3g^3+9g^2) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6g^4+3g^3-9g^2\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3g^2} $ by $ \left( -2g^2-g+3\right) $ $$ \color{blue}{3g^2} \cdot \left( -2g^2-g+3\right) = -6g^4-3g^3+9g^2 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(-6g^4-3g^3+9g^2 \right) = 6g^4+3g^3-9g^2 $$ |
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