Question
Answer
$$-2k(-2k\cdot2+3)=8k^2-6k$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-2k(-2k\cdot2+3)& \xlongequal{ }-2k(-4k+3) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(-8k^2+6k) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}8k^2-6k\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2k} $ by $ \left( -4k+3\right) $ $$ \color{blue}{2k} \cdot \left( -4k+3\right) = -8k^2+6k $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(-8k^2+6k \right) = 8k^2-6k $$ |
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