Question
Answer
$$-2j^2(2j^2+2j-4)=-4j^4-4j^3+8j^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-2j^2(2j^2+2j-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(4j^4+4j^3-8j^2) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-4j^4-4j^3+8j^2\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2j^2} $ by $ \left( 2j^2+2j-4\right) $ $$ \color{blue}{2j^2} \cdot \left( 2j^2+2j-4\right) = 4j^4+4j^3-8j^2 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(4j^4+4j^3-8j^2 \right) = -4j^4-4j^3+8j^2 $$ |
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