Question
Answer
$$-2d(-2d^2+4d)=4d^3-8d^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-2d(-2d^2+4d)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(-4d^3+8d^2) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4d^3-8d^2\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2d} $ by $ \left( -2d^2+4d\right) $ $$ \color{blue}{2d} \cdot \left( -2d^2+4d\right) = -4d^3+8d^2 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(-4d^3+8d^2 \right) = 4d^3-8d^2 $$ |
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