Question
Answer
$$-(z-b)^3=b^3-3b^2z+3bz^2-z^3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-(z-b)^3& \xlongequal{ }-(1z^3-3bz^2+3b^2z-b^3) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-z^3+3bz^2-3b^2z+b^3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}b^3-3b^2z+3bz^2-z^3\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left(z^3-3bz^2+3b^2z-b^3 \right) = -z^3+3bz^2-3b^2z+b^3 $$ |
| ② | Combine like terms: $$ b^3-3b^2z+3bz^2-z^3 = b^3-3b^2z+3bz^2-z^3 $$ |
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