Question
Answer
$$-(w-b)^3=b^3-3b^2w+3bw^2-w^3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-(w-b)^3& \xlongequal{ }-(1w^3-3bw^2+3b^2w-b^3) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-w^3+3bw^2-3b^2w+b^3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}b^3-3b^2w+3bw^2-w^3\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left(w^3-3bw^2+3b^2w-b^3 \right) = -w^3+3bw^2-3b^2w+b^3 $$ |
| ② | Combine like terms: $$ b^3-3b^2w+3bw^2-w^3 = b^3-3b^2w+3bw^2-w^3 $$ |
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