Question
Answer
$$-(6+2v^2-7v)+2+6v=-2v^2+13v-4$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-(6+2v^2-7v)+2+6v& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-6-2v^2+7v+2+6v \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-2v^2+13v-4\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left(6+2v^2-7v \right) = -6-2v^2+7v $$ |
| ② | Combine like terms: $$ \color{blue}{-6} -2v^2+ \color{red}{7v} + \color{blue}{2} + \color{red}{6v} = -2v^2+ \color{red}{13v} \color{blue}{-4} $$ |
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