Question
Answer
$$-(3-4x)(3x-3)=12x^2-21x+9$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-(3-4x)(3x-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(9x-9-12x^2+12x) \xlongequal{ } \\[1 em] & \xlongequal{ }-(-12x^2+21x-9) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12x^2-21x+9\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3-4x}\right) $ by each term in $ \left( 3x-3\right) $. $$ \left( \color{blue}{3-4x}\right) \cdot \left( 3x-3\right) = 9x-9-12x^2+12x $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(-12x^2+21x-9 \right) = 12x^2-21x+9 $$ |
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