Question
Answer
$$-(2x+6)^2(x-3)=-4x^3-12x^2+36x+108$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-(2x+6)^2(x-3)& \xlongequal{ }-(4x^2+24x+36)(x-3) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(4x^3-12x^2+24x^2-72x+36x-108) \xlongequal{ } \\[1 em] & \xlongequal{ }-(4x^3+12x^2-36x-108) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-4x^3-12x^2+36x+108\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4x^2+24x+36}\right) $ by each term in $ \left( x-3\right) $. $$ \left( \color{blue}{4x^2+24x+36}\right) \cdot \left( x-3\right) = 4x^3-12x^2+24x^2-72x+36x-108 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(4x^3+12x^2-36x-108 \right) = -4x^3-12x^2+36x+108 $$ |
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