| $$ \begin{aligned}-(2x-5y)^2& \xlongequal{ }-(4x^2-20xy+25y^2) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-4x^2+20xy-25y^2\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left(4x^2-20xy+25y^2 \right) = -4x^2+20xy-25y^2 $$ |