Question
Answer
$$(z-2)(4z+1)=4z^2-7z-2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(z-2)(4z+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4z^2+z-8z-2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4z^2-7z-2\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{z-2}\right) $ by each term in $ \left( 4z+1\right) $. $$ \left( \color{blue}{z-2}\right) \cdot \left( 4z+1\right) = 4z^2+z-8z-2 $$ |
| ② | Combine like terms: $$ 4z^2+ \color{blue}{z} \color{blue}{-8z} -2 = 4z^2 \color{blue}{-7z} -2 $$ |
This page was created using
Simplify polynomials calculator