Question
Answer
$$(y^3+3)^3=y^9+9y^6+27y^3+27$$
Explanation
| $$ \begin{aligned}(y^3+3)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}y^9+9y^6+27y^3+27\end{aligned} $$ | |
| ① | Find $ \left(y^3+3\right)^3 $ using formula $$ (A + B) = A^3 + 3A^2B + 3AB^2 + B^3 $$where $ A = y^3 $ and $ B = 3 $. $$ \left(y^3+3\right)^3 = \left( y^3 \right)^3+3 \cdot \left( y^3 \right)^2 \cdot 3 + 3 \cdot y^3 \cdot 3^2+3^3 = y^9+9y^6+27y^3+27 $$ |
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