Question
Answer
$$y^2+z^2-(14y^2+8yz-13z^2)=-13y^2-8yz+14z^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}y^2+z^2-(14y^2+8yz-13z^2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}y^2+z^2-14y^2-8yz+13z^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-13y^2-8yz+14z^2\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 14y^2+8yz-13z^2 \right) = -14y^2-8yz+13z^2 $$ |
| ② | Combine like terms: $$ \color{blue}{y^2} + \color{red}{z^2} \color{blue}{-14y^2} -8yz+ \color{red}{13z^2} = \color{blue}{-13y^2} -8yz+ \color{red}{14z^2} $$ |
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