Question
Answer
$$(xy^2)^3(x^2y)^2+x^3y^4(x^2y^2)^2=2x^7y^8$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(xy^2)^3(x^2y)^2+x^3y^4(x^2y^2)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^3y^61x^4y^2+x^3y^41x^4y^4 \xlongequal{ } \\[1 em] & \xlongequal{ }x^7y^8+x^7y^8 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^7y^8\end{aligned} $$ | |
| ① | $$ \left( xy^2 \right)^3 = 1^3x^3 \left( y^2 \right)^3 = x^3y^6 $$$$ \left( x^2y \right)^2 = 1^2 \left( x^2 \right)^2y^2 = x^4y^2 $$$$ \left( x^2y^2 \right)^2 = 1^2 \left( x^2 \right)^2 \left( y^2 \right)^2 = x^4y^4 $$ |
| ② | Combine like terms: $$ \color{blue}{x^7y^8} + \color{blue}{x^7y^8} = \color{blue}{2x^7y^8} $$ |
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