Question
Answer
$$(x+y-2)(2x-11y-8)=2x^2-9xy-11y^2-12x+14y+16$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x+y-2)(2x-11y-8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^2-9xy-11y^2-12x+14y+16\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x+y-2}\right) $ by each term in $ \left( 2x-11y-8\right) $. $$ \left( \color{blue}{x+y-2}\right) \cdot \left( 2x-11y-8\right) = 2x^2-11xy-8x+2xy-11y^2-8y-4x+22y+16 $$ |
| ② | Combine like terms: $$ 2x^2 \color{blue}{-11xy} \color{red}{-8x} + \color{blue}{2xy} -11y^2 \color{green}{-8y} \color{red}{-4x} + \color{green}{22y} +16 = \\ = 2x^2 \color{blue}{-9xy} -11y^2 \color{red}{-12x} + \color{green}{14y} +16 $$ |
This page was created using
Simplify polynomials calculator