Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x+y-1)(x-11y-16)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2-10xy-11y^2-17x-5y+16\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x+y-1}\right) $ by each term in $ \left( x-11y-16\right) $. $$ \left( \color{blue}{x+y-1}\right) \cdot \left( x-11y-16\right) = x^2-11xy-16x+xy-11y^2-16y-x+11y+16 $$ |
| ② | Combine like terms: $$ x^2 \color{blue}{-11xy} \color{red}{-16x} + \color{blue}{xy} -11y^2 \color{green}{-16y} \color{red}{-x} + \color{green}{11y} +16 = \\ = x^2 \color{blue}{-10xy} -11y^2 \color{red}{-17x} \color{green}{-5y} +16 $$ |