Question
Answer
$$(x+y-1)(2x-6y-16)=2x^2-4xy-6y^2-18x-10y+16$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x+y-1)(2x-6y-16)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^2-4xy-6y^2-18x-10y+16\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x+y-1}\right) $ by each term in $ \left( 2x-6y-16\right) $. $$ \left( \color{blue}{x+y-1}\right) \cdot \left( 2x-6y-16\right) = 2x^2-6xy-16x+2xy-6y^2-16y-2x+6y+16 $$ |
| ② | Combine like terms: $$ 2x^2 \color{blue}{-6xy} \color{red}{-16x} + \color{blue}{2xy} -6y^2 \color{green}{-16y} \color{red}{-2x} + \color{green}{6y} +16 = \\ = 2x^2 \color{blue}{-4xy} -6y^2 \color{red}{-18x} \color{green}{-10y} +16 $$ |
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