| $$ \begin{aligned}(x+7)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^3+21x^2+147x+343\end{aligned} $$ | |
| ① | Find $ \left(x+7\right)^3 $ using formula $$ (A + B) = A^3 + 3A^2B + 3AB^2 + B^3 $$where $ A = x $ and $ B = 7 $. $$ \left(x+7\right)^3 = x^3+3 \cdot x^2 \cdot 7 + 3 \cdot x \cdot 7^2+7^3 = x^3+21x^2+147x+343 $$ |