Question
Answer
$$(x+4)^3=x^3+12x^2+48x+64$$
Explanation
| $$ \begin{aligned}(x+4)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^3+12x^2+48x+64\end{aligned} $$ | |
| ① | Find $ \left(x+4\right)^3 $ using formula $$ (A + B) = A^3 + 3A^2B + 3AB^2 + B^3 $$where $ A = x $ and $ B = 4 $. $$ \left(x+4\right)^3 = x^3+3 \cdot x^2 \cdot 4 + 3 \cdot x \cdot 4^2+4^3 = x^3+12x^2+48x+64 $$ |
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